1/7(x-2)^2=56

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Solution for 1/7(x-2)^2=56 equation: 


x in (-oo:+oo)

(1/7)*(x-2)^2 = 56 // - 56

(1/7)*(x-2)^2-56 = 0

1/7*(x-2)^2-56 = 0

1/7*(x-2)^2-56 = 0

1/7*x^2-4/7*x-388/7 = 0

1/7*x^2-4/7*x-388/7 = 0

1/7*(x^2-4*x-388) = 0

x^2-4*x-388 = 0

DELTA = (-4)^2-(-388*1*4)

DELTA = 1568

DELTA > 0

x = (1568^(1/2)+4)/(1*2) or x = (4-1568^(1/2))/(1*2)

x = (28*2^(1/2)+4)/2 or x = (4-28*2^(1/2))/2

1/7*(x-((4-28*2^(1/2))/2))*(x-((28*2^(1/2)+4)/2)) = 0

1/7*(x-((4-28*2^(1/2))/2))*(x-((28*2^(1/2)+4)/2)) = 0

( 1/7 )

1/7 = 0

x belongs to the empty set

( x-((28*2^(1/2)+4)/2) )

x-((28*2^(1/2)+4)/2) = 0 // + (28*2^(1/2)+4)/2

x = (28*2^(1/2)+4)/2

( x-((4-28*2^(1/2))/2) )

x-((4-28*2^(1/2))/2) = 0 // + (4-28*2^(1/2))/2

x = (4-28*2^(1/2))/2

x in { (28*2^(1/2)+4)/2, (4-28*2^(1/2))/2 }

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